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Complete factorization of x^3+4x^2-20x-48

User Binaya
by
4.0k points

1 Answer

1 vote

Answer:

(x + 6) • (x + 2) • (x - 4)

Explanation:

STEP

1

:

Equation at the end of step 1

(((x3) + 22x2) - 20x) - 48

STEP

2

:

Checking for a perfect cube

2.1 x3+4x2-20x-48 is not a perfect cube

Trying to factor by pulling out :

2.2 Factoring: x3+4x2-20x-48

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: x3-48

Group 2: 4x2-20x

Pull out from each group separately :

Group 1: (x3-48) • (1)

Group 2: (x-5) • (4x)

User Zaur Nasibov
by
3.4k points