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The quadratic equation whose roots are 3-√3 and 3+√3​

1 Answer

5 votes

Answer:

x²-6x +6

Step-by-step explanation:

in general (x-root1) (x-root2) will give you the equation

for our case, the equation is given by

(x-3+√3)(x-3-√3), distribute

x²-3x-x√3 -3x+9+3√3+x√3-3√3-√9, group like terms and substitute √9 by 3

x²+(-3 -√3 -3 +√3)x +(9 +3√3 -3√3 -3), combine like terms

x²-6x +6

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