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Example to measure the interval of time of a small stone dropped from 1m height.

User Kaligule
by
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1 Answer

3 votes

Answer:

The time required is 0.45 s.

Step-by-step explanation:

Height, h = 1 m

initial velocity, u = m/s

Let the time is t.

Use second equation of motion


h = u t + 0.5 at^2\\\\1 = 0 +0.5 * 9.8 * t^2\\\\t = 0.45 s