Question

Two cubic meters of a gas at 303 K are heated at constant pressure until the volume is doubled. What is the final temperature of the gas?

Answer 1

`V_1 = {2 \: m}^(3)`

`T_1 = 303 \: k`

`V_2 = 2(V_1) = 2(2) = 4 \: {m}^(3)`

`T_2 = ?`

Here, it's mentioned that the pressure is constant.

By Charles law :

`\implies V \propto T \\`

`\implies (V_1)/(V_2) = (T_1)/(T_2) \\`

`\implies (2)/(4) = (303)/(T_2)`

`\implies (T_2)/(4) = (303)/(2)`

`\implies T_2 = (303 * 4)/(2)`

`\implies T_2 = (1212)/(2)`

`\implies T_2 = 606 \: k`