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If the area of a rectangle is x^2 + 10x + 21 and the width is x + 7, then what is the perimeter? a) 4x + 20 b) 2x + 14 c) 2x + 10
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If the area of a rectangle is x^2 + 10x + 21 and the

width is x + 7, then what is the perimeter?
a) 4x + 20
b) 2x + 14
c) 2x + 10

User Ben Beirut
by
6.6k points

1 Answer

4 votes

4x+20

OPTION A is the correct answer.

If the area of a rectangle is x^2 + 10x + 21 and the width is x + 7, then what is-example-1
If the area of a rectangle is x^2 + 10x + 21 and the width is x + 7, then what is-example-2
If the area of a rectangle is x^2 + 10x + 21 and the width is x + 7, then what is-example-3
If the area of a rectangle is x^2 + 10x + 21 and the width is x + 7, then what is-example-4
User Nick LK
by
6.9k points
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