(27)^3+(-15)+(12)^3
= 27×27×27-15+12×12×12
= 19683-15+1728
= 21396 answer........
(27)³ + (-15)³ + (12)³
Let, x = 27, y = -15, z = 12
Then, x + y + z = 27 - 15 + 12 = 0
We know the algebraic identity, if a + b + c = 0 then a³ + b³ + c³ = 3abc
Thus, (27)³ + (-15)³ + (12)³ = 3×(27)(-15)(12)
= -14580
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