Answer:
True
Step-by-step explanation:
The tensile stress, σ, on a solid cylindrical wire is given by the following relationship;
![\sigma = (F_t)/(A_o)](https://img.qammunity.org/2022/formulas/physics/high-school/zgmotcddvmw6njvf4keb8iyuaa91qe0y1d.png)
Where;
= The tensile force
= The original cross sectional area of the cylindrical wire = π·R²
R = The radius of the wire
Therefore;
= σ ×
= σ × π × R²
Therefore, the tensile force is directly proportional to the square of the radius of the cylindrical wire, and as the radius of the wire increases, which is by increasing the thickness of the wire, the tensile force is largely increased
The correct option is; True.