Question

Un tren viaja inicialmente a 16m/s se acelera constantemente a razón de 2m/s2 en la misma dirección. ¿Cuán lejos viajará en 20s?

Answer 1

The train will travel a distance of 400 meters in 20 seconds.

Step-by-step explanation:

To find the distance traveled by the train in 20 seconds, we first need to find the final velocity of the train after 20 seconds of acceleration. Using the equation v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time, we can substitute the given values to find the final velocity: v = 16 m/s + 2 m/s² * 20 s = 56 m/s.

Next, we can use the equation s = ut + (1/2)at², where s is the distance traveled, t is the time, u is the initial velocity, and a is the acceleration. Since the train is initially at rest, the equation simplifies to s = (1/2)at². We can substitute the values to find the distance traveled: s = (1/2) * 2 m/s² * (20 s)² = 400 m.

Therefore, the train will travel a distance of 400 meters in 20 seconds.

Next, we can use the equation s = ut + (1/2)at², where s is the distance traveled, t is the time, u is the initial velocity, and a is the acceleration. Since the train is initially at rest, the equation simplifies to s = (1/2)at². We can substitute the values to find the distance traveled: s = (1/2) * 2 m/s² * (20 s)² = 400 m.

Therefore, the train will travel a distance of 400 meters in 20 seconds.

Answer 2

d = 720 s

Step-by-step explanation:

The question says, "A train initially traveling at 16m / s accelerates constantly at a rate of 2m / s2 in the same direction. How far will it travel in 20s?"

Initial speed, u = 16 m/s

Acceleration, a = 2m/s²

We need to find the distance covered by it in 20 seconds. Let the distance is d. Using the second equation of motion,

`d=ut+(1)/(2)at^2\\\\d=16* 20+(1)/(2)* 2* 20^2\\\\d=720\ m`

So, it will cover 720 m in 20 seconds.