Question

Suppose the function of h is defined, for all real numbers as follows: (f) x = -3 if x is <) 3 if x is =0 -2 if x is > 0

Answer 1

See explanation

Explanation:

The question is not properly presented; I will answer this with the following similar question.

`h(x) = -(1)/(3)x^2 + 4` ---
`x \\e 2`

`h(x) = -4` ---
`x= 2`

Required

`h(-5)\ \&\ h(2)`

Calculating h(-5)

This implies that: x = -5

`-5 \\e 2`

So, we make use of:

`h(x) = -(1)/(3)x^2 + 4`

Substitute -5 for x

`h(-5) = -(1)/(3) * (-5)^2 + 4`

`h(-5) = -(1)/(3) * 25 + 4`

`h(-5) = -(25)/(3) + 4`

Take LCM

`h(-5) = (-25+12)/(3)`

`h(-5) = -(13)/(3)`

Calculating h(2)

This implies that: x = 2

`2 = 2`

So, we make use of:

`h(x) = -4`

Substitute 2 for x

`h(2) = -4`

Use the above explanation to answer your question