Suppose the function of h is defined, for all real numbers as follows: (f) x = -3 if x is <) 3 if x is =0 -2 if x is > 0

Question

asked Mar 21, 2022 54.1k views

1 Answer

Duffydake · Answer 1 · 2022-03-25T16:40:00+0000

Answer:

See explanation

Explanation:

The question is not properly presented; I will answer this with the following similar question.

h(x) = -(1)/(3)x^2 + 4 ---
$x \\e 2$

h(x) = -4 ---
x= 2

Required

$h(-5)\ \&\ h(2)$

Calculating h(-5)

This implies that: x = -5

$-5 \\e 2$

So, we make use of:

h(x) = -(1)/(3)x^2 + 4

Substitute -5 for x

h(-5) = -(1)/(3) * (-5)^2 + 4

h(-5) = -(1)/(3) * 25 + 4

h(-5) = -(25)/(3) + 4

Take LCM

h(-5) = (-25+12)/(3)

h(-5) = -(13)/(3)

Calculating h(2)

This implies that: x = 2

2 = 2

So, we make use of:

h(x) = -4

Substitute 2 for x

h(2) = -4

Use the above explanation to answer your question