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Does anyone know how to do this help please

Does anyone know how to do this help please-example-1

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Answer:


\boxed{\begin{array}c \bf x &\rm -3 &\rm -2 &\rm -1 &\rm 0 &\rm 1 &\rm 2 &\rm 3 \\\\ \bf y & \rm 0 &\rm -4 &\rm -6&\rm -6 &\rm -4&\rm 2 &\rm 6 \end{array}}

Explanation:

A quadratic function is given to us . And we need to fill out the table by using the function . The given function is ,


\rm\implies y = x^2+x - 6

Here we need to substitute the different values of x , to get the different values of y.

Put x = -3 :-


\rm\implies y = 3^2-3-6\\


\rm\implies y = 9 - 3 - 6 \\


\rm\implies y = 0

Put x = -2 :-


\rm\implies y = 2^2-2-6\\


\rm\implies y = 4 -2-6\\


\rm\implies y = -4

Put x = -1 :-


\rm\implies y = -1^2-1-6\\


\rm\implies y = 1 -1-6 \\


\rm\implies y = -6

Put x = 1 :-


\rm\implies y = 1^2+1-6\\


\rm\implies y = 2 -6


\rm\implies y = -4

Put x = 2 :-


\rm\implies y = 2^2+2-6\\


\rm\implies y = 4 +2-6\\


\rm\implies y = 2

Put x = 3 :-


\rm\implies y = 3^2+3-6\\


\rm\implies y = 9 +3-6\\


\rm\implies y = 6

Final table :-


\boxed{\begin{array}c \bf x &\rm -3 &\rm -2 &\rm -1 &\rm 0 &\rm 1 &\rm 2 &\rm 3 \\\\ \bf y & \rm 0 &\rm -4 &\rm -6&\rm -6 &\rm -4&\rm 2 &\rm 6 \end{array}}

User CJCombrink
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