Greatest common factor of 26m^4n^2, m^2n

asked Dec 1, 2022 149k views

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Explanation:

Hey there!

Given;

$1st \: expn = 26 {m}^(4) {n}^(2)$

= 2*13 m⁴ n²

2nd expn = m² n

Therefore, greatest common factor is; m²n.

Hope it helps!

NeedAnswers answered Dec 5, 2022

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