Question

How do I do this question

Answer 1

Explanation:

Join OB.

∠A=∠A (common)

`(AP)/(AO) =((1)/(2) AO)/(AO) =(1)/(2) \\(AQ)/(AB) =((1)/(2) AB)/(AB) =(1)/(2) \\(AP)/(AO) =(AQ)/(AB)`

∴ ΔAPO and ΔAOB are similar.

`(PQ)/(OB) =(1)/(2) \\`

∠P=∠O

∠Q=∠B

So PQ║OB

Similarly RS║OB

∴PQ║RS