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Asap answer pls-----------

Asap answer pls------------example-1

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Answer:


y=(4)/(5)x-(18)/(5)

Explanation:

Hi there!

Linear equations are typically organized in slope-intercept form:
y=mx+b where m is the slope and b is the y-intercept (the value of y when x is 0).

1) Determine the slope (m)


m=(y_2-y_1)/(x_2-x_1) where two points on the line are
(x_1,y_1) and
(x_2,y_2)

In the graph, the points (-3,-6) and (2,-2) are plotted clearly, so we can use these to help us find the slope. Plug them into the equation:


m=(-6-(-2))/(-3-2)\\m=(-6+2)/(-3-2)\\m=(-4)/(-5)\\m=(4)/(5)

Therefore, the slope of the line is
(4)/(5). Plug this into
y=mx+b :


y=(4)/(5)x+b

2) Determine the y-intercept (b)


y=(4)/(5)x+b

Typically, given a graph, we could look at where exactly the line crosses the y-axis to determine b. However, because it appears ambiguous on this graph, we must solve it algebraically.

Plug in one of the given points (2,-2) and solve for b:


-2=(4)/(5)(2)+b\\-2=(8)/(5)+b

Subtract
(8)/(5) from both sides to isolate b


-2-(8)/(5)=(8)/(5)+b-(8)/(5)\\-(18)/(5) =b

Therefore, the y-intercept of the line is
-(18)/(5). Plug this back into
y=(4)/(5)x+b:


y=(4)/(5)x+(-(18)/(5))\\y=(4)/(5)x-(18)/(5)

I hope this helps!

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