Question

Hey are In 1990 oranges cost $0.56 per pound. In 2003 they cost $0.86 per pound. How 0 35. much did the oranges appreciate (percent of increase)?

SHOW YOUR WORK.​

Answer 1

`\boxed{\large{\bold{\blue{ANSWER~:) }}}}`

Given:-

• are In 1990 oranges cost $0.56 per pound. In 2003 they cost $0.86 per pound

Find:-

• percentage of increasing

Solution:-

we have, 1990 oranges cost $0.56 per pound. In 2003 they cost $0.86 per pound.

so,

• C.P of 1990=0.56$
• c.p of 2003=0.86$

`\sf{increase_((profit))=0.86-0.56=0.3 }`

we know that,

`\bold{ profit\%=(profit)/(C.P)×100 }`

According to the question,

• 
  `\sf{percentage_((profit))=(0.3)/(0.56)×100 }`

• 
  `\sf{percentage_((profit))=(5357)/(100) }`

• 
  `\sf{percentage_((profit))=53.57\% }`

Answer 2

Solution given:

in 1990

cost of orange[C.P]=$0.56

in 2003

cost of orange[S.P]=$0.86

now

increased price[profit]=S.P-C.P=$0.86-$0.56=$0.3

Now

increased percent [profit%]=?

we have

profit%=profit/c.p*100%

=0.3/0.56*100=53.57℅

Therefore

the oranges appreciated by 53.57%