Answer:
Surface area = 21 in.²
Explanation:
Surface area of the pyramid = sum of all areas of the faces or parts of the net = 4(area of triangle) + area of square base
✔️Area of the four triangles:
A = 4(½*b*h)
Where,
b = 3 in.
h = 2 in.
A = 4(½*3*2)
A = 2*3*2
A = 12 in.²
✔️Area of the square base = s²
s = 3 in.
Area = 3² = 9 in.²
✅Surface area of the pyramid = 12 + 9 = 21 in.²