Question

How many moles of KClO3 must decompose in order to produce 9 moles of oxygen gas (O2) using the following reaction by completing the t-chart below.

Answer 1

Answer: 6 moles of
`KClO_3` will be decomposed.

Step-by-step explanation:

We are given:

Moles of oxygen gas produced = 9 moles

The chemical equation for the decomposition of
`KClO_3` follows:

`2KClO_3\rightarrow 2KCl+3O_2`

By the stoichiometry of the reaction:

If 3 moles of oxygen gas is produced by 2 moles of
`KClO_3`

So, 9 moles of oxygen gas will be produced by =
`(2)/(3)* 9=6mol` of
`KClO_3`

Hence, 6 moles of
`KClO_3` will be decomposed.