1 Answer

Vicky Chijwani · Answer 1 · 2022-08-15T08:18:56+0000

Answer:

Explanation:

sin²β + sin²β×tan²β = tan²β

sin²β( 1 + tan²β ) = tan²β

~~~~~~~~~~~~~~~~

sin²β + cos²β = 1

$(sin^2\beta )/(cos^2\beta )$ +
$(cos^2\beta )/(cos^2\beta )$ =
$(1)/(cos^2\beta )$ ⇒ tan²β + 1 = sec²β ⇔ 1 + tan²β = sec²β

~~~~~~~~~~~~~~

1 + tan²β =
$(1)/(cos^2 \beta )$

L.H. = sin²β (
$(1)/(cos^2 \beta )$ ) = tan²β

R.H. = tan²β

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