1.621 kN
Explanation:
Let the centerline of the canal be the x-axis. Because the forces exerted by the horses are symmetric to the centerline, only the x-components of these forces contribute to the resultant force on the barge, i.e., the y-components cancel out. Each x-component is equal to
= 810.4 N. Therefore, the resultant force on the barge is twice this:
![F_(net) = 2(839\:\text{N})\cos 15 = 1620.8\:\text{N}](https://img.qammunity.org/2022/formulas/mathematics/college/nihbtbe8pmr00z985915gbrqnrifcxkikv.png)
![= 1.621\:\text{kN}](https://img.qammunity.org/2022/formulas/mathematics/college/u412qltjc2g9v9a3yu2strjbfezp0mtrwr.png)