Answer:
(x-3)^2+y^2=8
Explanation:
I'm going to go ahead and assume the center is (3,0). The radius can be found by computing the distance from the center, (3,0), to a point on the circle, (5,-2).
The distance between two points is calculated by doing sqrt((distance between x's)^2+(distance between y's)^2).
The distance between our x's is 2.
The distance between our y's is 2.
The square of each then is 4 and 4 respectively.
So we have the distance is sqrt(4+4)=sqrt(8).
The radius is sqrt(8).
The equation of a circle is (x-h)^2+(y-k)^2=r^2 where (h,k) is center and r is radius.
If r=sqrt(8), then r^2=8.
(h,k)=(3,0)
(x-h)^2+(y-k)^2=r^2
(x-3)^2+(y-0)^2=8
(x-3)^2+y^2=8