Question

2. Caveman Sampson chases a saber tooth tiger at an average speed of 3 miles per hour. The tiger runs at an average speed of 5 miles per hour, but rests for 2 hours after running for 2 hours. How long, in hours, will it take Sampson to catch the tiger if the tiger starts 2 miles in front of him and they start running at the same time?

A. 7 hours B. 6 hours C. 5 hours D. 4 hours​

Answer 1

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Answer:

D. 4 hours

Explanation:

The tiger will run (5 mi/h)(2 h) = 10 mi in 2 hours. That will put it 2+10 = 12 miles from Sampson's starting location.

Samson can run 12 miles in time ...

time = distance/speed = (12 mi)/(3 mi/h) = 4 h

Sampson will get to the tiger's location after 4 hours, just as the tiger is ending its rest period.

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The graph shows the position of Sampson (red) and the tiger (blue) x hours after the chase starts. The distance (y miles) is measured from Sampson's starting point, assuming the tiger is running away.