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The distance between (-4,-5) and (4,2)

User Csierra
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1 Answer

4 votes

Answer:

rida22 this is the third of these you asked for...

do you need help on the steps???

the solution is using the Pythagorean theorem (a^2 + b^2 = c^2)

so distance "A" = x1-x2 which is 4 - (-4) in your problem = 8


a^2 + b^2 = c^2


8^2 + b^2 = c^2

"B" = y1-y2 = -5 - 2 = -7


8^2 + (-7)^2 = c^2

64 + 49 = c^2

c^2 = 113

c =
√(113)

Explanation:

User Preethi
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