Question

Please evaluate P(7,1)

Answer 1

7

Explanation:

Using the definition

n
`P_(r)` =
`(n!)/((n-r)!)`

where n! = n(n - 1)(n - 2)..... 3 × 2 × 1

Then

7
`P_(1)` =
`(7!)/((7-1)!)` =
`(7!)/(6!)` ← cancel out the multiples 6 ×5 × 4 × 3 × 2 × 1 , then

7
`P_(1)` = 7