Question

How to bring the polynomial to the standard form p(x) x^2-2x+4) (x^2+2x+4) ​

Answer 1

`\rightarrow\sf((p(x) {x}^(2) + 2x + 4)( {x}^(2) + 2x + 4)) \\ = \sf {ax}^(2) + bx + c \\ = \sf(p(x) {x}^(2) {x}^(2) + p(x) {x}^(2) (2x) + p(x) {x}^(2) * 4 + 2x * {x}^(2) + 2x(2x) + 2x * 4 + {4x}^(2) + 4(2x) + 4 * 4) \\ = \sf( {x}^(4) p(x) + {2x}^(3) p(x) + {4x}^(2) p(x) + {2x}^(3) + {8x}^(2) + 16x + 16) \\ \rightarrow \large\boxed{\sf\red{{{x}^(4) p(x) + {2x}^(3) p(x) + {4x}^(2) p(x) + {2x}^(3) + {8x}^(2) + 16x + 16}}}`

Answer:

`\large\boxed{\sf{\red{{x}^(4) p(x) + {2x}^(3) p(x) + {4x}^(2) p(x) + {2x}^(3) + {8x}^(2) + 16x + 16}}}`

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