Question

Need Help this is due in 30 minutes!

Answer 1

E

Explanation:

Since all the numbers are hundredths decimals, let multiply by the power of 2 of the base 10. So let multiply the equation by

`10 {}^(2)`

So our new equation is

`3 3{x}^(2) + 71x - 14 = 0`

Solve by AC method

`ac = - 462`

`b = 71`

We must think of two numbers that

Multiply to -462 and Add to 71. Set up equation

The numbers are 77 and -6.

So our new equation is

`{33x}^(2) + 77x - 6x - 14 = 0`

Solve by factoring by grouping

`(33 {x}^(2) + 77x) - (6x - 14)`

Factor out 11 for the first equation

`11x(3x + 7) - 2(3x + 7)`

So our factors are

`(11x - 2)(3x + 7)`

Set each equal to zero

`11x - 2 = 0`

`11x = 2`

`x = (2)/(11)`

`3x + 7 =`

`3x = - 7`

`x = ( - 7)/(3)`