Question

A 6.90 kg block is at rest on a horizontal floor. If you push horizontally on the 6.90 kg block with a force of 12.0 N. It just

starts to move.
What is the coefficient of static friction?
Numeric Response

Answer 1

`\mu = 0.177`

Step-by-step explanation:

Let's look at the forces on the two axes:

`x:\:\:\:F - f_n = F - \mu N = 0\:\:\:\:\:\;(1)`

`y:\:\:\:N - mg = 0\:\:\:\:\:\:\:\:\:(2)`

Substituting (2) into (1) and solving for
`\mu`, we get

`F = \mu mg`

`\mu = (F)/(mg) = \frac{12.0\:\text{N}}{(6.9\:\text{kg})(9.8\:\text{m/s}^2)} = 0.177`