Question

The rate constant for a particular second order reaction is 2.4 x 10-2 M-1 s-1 at 35∘C. If the initial concentration of the reactant is 1.20 M, what is the concentration (in M) after 4 minutes?

Answer 1

`C_2=0.21M`

Step-by-step explanation:

From the question we are told that:

Rate constant
`K=2.4 x*10^(-2) M-1 s-1`

Temperature
`T=35^o`

Initial concentration
`C_1=1.20M`

Time
`T=4min=>240sec`

Generally the equation for second order reacion is mathematically given by

`(1)/(C_2) = (1)/(C_1) +Kt`

`(1)/(C_2) = (1)/(1.2 ) +2.4 * 10^(-2) *240`

`(1)/(C_2) = 4.8`

`C_2=0.21M`