Answer:
![Pr =(1)/(38955840)](https://img.qammunity.org/2022/formulas/mathematics/college/mdt8b7cwesrml1nallig2e56qgm5jh67cv.png)
Explanation:
Given
---- 1 to 35
-- selection
Required
The probability of winning
The probability of getting the first number correctly is:
![P(1) = (1)/(35)](https://img.qammunity.org/2022/formulas/mathematics/college/vc35iek61a4djj6jyqccro5mfz2v0p8tqc.png)
At this point, the remaining numbers are 34
So, the second selection has the following probability
![P(2) = (1)/(34)](https://img.qammunity.org/2022/formulas/mathematics/college/py2prm6acioxj4ebh22jxxx7wnjfk4w3nn.png)
Following the above sequence, we have:
![P(3) = (1)/(33)](https://img.qammunity.org/2022/formulas/mathematics/college/ff3w1v7vr49u0fvb7wgsawzilfkysbuemh.png)
![P(4) = (1)/(32)](https://img.qammunity.org/2022/formulas/mathematics/college/t9iz7wshf79z7opq5nfzbytu8rwp2k791p.png)
![P(5) = (1)/(31)](https://img.qammunity.org/2022/formulas/mathematics/college/1tbmzkfvzrtssfvroh97rzk7mjvngm6adw.png)
So, the required probability is:
![Pr =P(1) * P(2) * P(3) * P(4) * P(5)](https://img.qammunity.org/2022/formulas/mathematics/college/tssuk3685hexabutew83ra0xt9g5avtxcq.png)
![Pr =(1)/(35) *(1)/(34)*(1)/(33)*(1)/(32)*(1)/(31)](https://img.qammunity.org/2022/formulas/mathematics/college/staaal8o5pif7lvl6d1m7t64vo795xqgu2.png)
![Pr =(1)/(35*34*33*32*31)](https://img.qammunity.org/2022/formulas/mathematics/college/3hxwyh0o01doxaq7n2lsy76r12e7ak12ky.png)
![Pr =(1)/(38955840)](https://img.qammunity.org/2022/formulas/mathematics/college/mdt8b7cwesrml1nallig2e56qgm5jh67cv.png)