Question

A 0.40-kg mass attached to the end of a string swings in a vertical circle having a radius of 1.8 m. At an instant when the string makes an angle of 40 degrees below the horizontal, the speed of the mass is 5.0 m/s. What is the magnitude of the tension in the string at this instant

Answer 1

`T=8.1N`

Step-by-step explanation:

From the question we are told that:

Mass m=0.40

Radius r=1.8m

Angle Beneath the Horizontal \theta =40 \textdegree

Speed v=5.0m/s

The Tension Angle

`\alpha=90-\theta\\\\\alpha=90-40`

`\alpha=50 \textdegree`

Generally the equation for Tension is is mathematically given by

`T=(mv^2)/(r)+mgcos \alpha`

`T=(0.40*5^2)/(1.8)+0.40*5cos50`

`T=8.1N`