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Thermodynamic Processes: An ideal gas is compressed isothermally to one-third of its initial volume. The resulting pressure will be

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Answer:

The resulting pressure is 3 times the initial pressure.

Step-by-step explanation:

The equation of state for ideal gases is described below:


P\cdot V = n \cdot R_(u)\cdot T (1)

Where:


P - Pressure.


V - Volume.


n - Molar quantity, in moles.


R_(u) - Ideal gas constant.


T - Temperature.

Given that ideal gas is compressed isothermally, this is, temperature remains constant, pressure is increased and volume is decreased, then we can simplify (1) into the following relationship:


P_(1)\cdot V_(1) = P_(2)\cdot V_(2) (2)

If we know that
(V_(2))/(V_(1)) = (1)/(3), then the resulting pressure of the system is:


P_(2) = P_(1)\cdot \left((V_(1))/(V_(2)) \right)


P_(2) = 3\cdot P_(1)

The resulting pressure is 3 times the initial pressure.

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