Answer:
The minimum initial speed of the cannon ball is approximately 99.018 m/s
Step-by-step explanation:
The parameters of the cannon are;
The maximum horizontal distance reached, R = 3,279 ft. ≈ 999.4392 m
The maximum horizontal range,
, is given by the following formula;

Where;
u = The initial speed
g = The acceleration due to gravity ≈ 9.81 m/s²
= 999.4392 m
We get;
u = √(g ×
)
∴ u = √(9.81 m/s² × 999.4392 m) ≈ 99.018 m/s
The minimum initial speed of the cannon ball (just as it leaves the cannon) that is needed for it to reach this distance, in m/s, u ≈ 99.018 m/s.