185k views
1 vote
A set of quiz scores has a mean of 78 and a standard deviation of 9. Using a common grading scale where 60 and above is a passing score, what percentage of the

students passed this test?
Explain your answer in terms of the 68-95-99.7 rule.

User Datajam
by
7.6k points

1 Answer

2 votes

Answer:

97.5% of the students passed this test.

Explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean of 78, standard deviation of 9.

What percentage of the students passed this test?

Above 60.

60 = 78 - 2*9

So 60 is two standard deviations below the mean.

The normal distribution is symmetric, which means that 50% of the measures are above the mean and 50% are below.

Of the 50% above, all passed.

Of the 50% below, 95%(within 2 standard deviations of the mean) passed.

So


p = 0.5 + 0.5*0.95 = 0.975

97.5% of the students passed this test.

User KevenK
by
7.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories