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What is the total kinetic energy of a 0.15 kg hockey puck sliding at 0.5 m/s and rotating about its center at 8.4 rad/s

User Dave Delay
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1 Answer

3 votes

Answer:


K=0.023J

Step-by-step explanation:

From the question we are told that:

Mass
m=0.15

Velocity
v=0.5m/s

Angular Velocity
\omega=8.4rad/s

Generally the equation for Kinetic Energy is mathematically given by


K=(1)/(2)M(v^2+(1)/(2)R^2\omega^2)


K=(1)/(2)0.15(0.5^2+(1)/(2)(0.038)^2.(8.4rad/s^2))


K=0.023J

User DmitryB
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5.0k points