Question

You prepare a solution by dissolving 25.3 g sucrose (C12H22O11) 705 mL of water. Calculate the molarity of the solution.

Answer 1

0.105 M

Step-by-step explanation:

First we convert 25.3 grams of sucrose into moles, using sucrose's molar mass:

• Molar Mass of C₁₂H₂₂O₁₁ = 342.3 g/mol

• 25.3 g C₁₂H₂₂O₁₁ ÷ 342.3 g/mol = 0.0739 mol C₁₂H₂₂O₁₁

Now we calculate the molarity of the solution, using the given volume and the calculated number of moles:

• Converting 705 mL ⇒ 705 mL / 1000 = 0.705 L

• Molarity = 0.0739 mol / 0.705 L = 0.105 M