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9 votes
9 votes
You push an object initially at rest across a frictionless floor

User Peter Herdenborg
by
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1 Answer

14 votes
14 votes

t = t₀ / 2

Step-by-step explanation:

In this exercise we must use Newton's second law

F = m a

a = F / m

now we can use kinematics

as in object part of rest (v₀ = 0)

v =a t₀

t₀ = v / a

these results are with the first experiment

now repeat the experiment, but F = 2F₀

a = 2F₀ / m = 2 a₀

v = 2 a₀ t

t = v / 2a₀

t = t₀ / 2

User Languitar
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