Answer:
5.1 cm
Explanation:
(Probable) Question;
Given a circle with center O and radius 2.4 cm. P is a point on the tangent that touches the circle at point Q, such that the length of the tangent from P to Q is 4.5 cm. Find the length of OP
The given parameters are;
The radius of the circle with enter at O,
= 2.4 cm
The length of the tangent from P to the circle at point Q,
= 4.5 cm
The length of OP = Required
By Pythagoras's theorem, we have;
² =
² +
²
∴
² = 2.4² + 4.5² = 26.01
= √26.01 = 5.1
The length of OP = 5.1 cm