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What is the equation of a circle with its center at (−6,−3) and a radius of 12?

2 Answers

1 vote

Answer:

x² + y² + 12x +6y - 99 = 0

Explanation:

Given :

  • Centre = (-6,-3)
  • Radius = 12 ,

Using the Standard equation of circle ,

  • ( x - h)² + (y-k)² = r²
  • ( x +6)² + (y+3)² = 12²
  • x² + 36 + 12x + y² + 9 + 6y = 144
  • x² + y² + 12x + 6y +45-144 = 0
  • x² + y² + 12x +6y - 99 = 0
User Tom Sun
by
8.8k points
5 votes

Answer:

(x+6)^2 + ( y +3)^2 = 144

Explanation:

The equation of a circle is given by

(x-h)^2 +(y-k)^2 = r^2 where (h,k) is the center and r is the radius

(x- -6)^2 + ( y - -3)^2 = 12^2

(x+6)^2 + ( y +3)^2 = 144

User CrazyPen
by
7.7k points

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