Question

What is the missing constant term in the perfect square that starts with x2 – 12x ?

Answer 1

x^2 -12x+36

Explanation:

x^2 – 12x

Take the coefficient of x

-12

Divide by 2

-12/2 = 6

Square it

6^2 = 36

We need to add 36 to make x^2 -12x a perfect square trinomial

x^2 -12x+36