Question

Log6^(4x-5)=Log6^(2x+1)

Answer 1

`x = 3`

Explanation:

Given

`\log6^((4x-5)) =\log6^((2x+1))`

Required

Solve for x

We have:

`\log6^((4x-5)) =\log6^((2x+1))`

Remove log6 from both sides

`(4x-5) = (2x+1)`

Collect like terms

`4x - 2x = 5 + 1`

`2x = 6`

Divide by 2

`x = 3`