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Write an equilibrium expression for each chemical equation involving one or more solid or liquid reactants or products.

User Chase Ries
by
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1 Answer

2 votes

Answer:

a.


Keq=([HCO_3^-][OH^-])/([CO_3^(2-)])

b.


Keq=[O_2]^3

c.


Keq=([H_3O^+][F^-])/([HF])

d.


Keq=([NH_4^+][OH^-])/([NH_3])

Step-by-step explanation:

Hello there!

In this case, for the attached reactions, it turns out possible for us to write the equilibrium expressions by knowing any liquid or solid would be not-included in the equilibrium expression as shown below, with the general form products/reactants:

a.


Keq=([HCO_3^-][OH^-])/([CO_3^(2-)])

b.


Keq=[O_2]^3

c.


Keq=([H_3O^+][F^-])/([HF])

d.


Keq=([NH_4^+][OH^-])/([NH_3])

Regards!

Write an equilibrium expression for each chemical equation involving one or more solid-example-1
User Galethil
by
5.5k points