Answer:
The power consumed in the lamp marked 100W - 110V is 15.68W
The power consumed in the lamp marked 100W - 220V is 62.73W
Explanation:
Given:
First lamp rating
Power (P) = 100W
Voltage (V) = 110V
Second lamp rating
Power (P) = 100W
Voltage (V) = 220V
Source
Voltage = 220V
i. Get the resistance of each lamp.
Remember that power (P) of each of the lamps is given by the quotient of the square of their voltage ratings (V) and their resistances (R). i.e
P =
![(V^2)/(R)](https://img.qammunity.org/2022/formulas/mathematics/college/jxmn0tzdx6lpcalfyks2x5djzfss3dau62.png)
Make R subject of the formula
⇒ R =
------------------(i)
For first lamp, let the resistance be R₁. Now substitute R = R₁, V = 110V and P = 100W into equation (i)
R₁ =
![(110^2)/(100)](https://img.qammunity.org/2022/formulas/mathematics/college/yornv7xybx3t34awgr1x9o7p22walvfc0c.png)
R₁ = 121Ω
For second lamp, let the resistance be R₂. Now substitute R = R₂, V = 220V and P = 100W into equation (i)
R₂ =
![(220^2)/(100)](https://img.qammunity.org/2022/formulas/mathematics/college/50gbv30rvm3hk7755zgryqx0jngc3y8zlt.png)
R₂ = 484Ω
ii. Get the equivalent resistance of the resistances of the lamps.
Since the lamps are connected in series, their equivalent resistance (R) is the sum of their individual resistances. i.e
R = R₁ + R₂
R = 121 + 484
R = 605Ω
iii. Get the current flowing through each of the lamps.
Since the lamps are connected in series, then the same current flows through them. This current (I) is produced by the source voltage (V = 220V) of the line and their equivalent resistance (R = 605Ω). i.e
V = IR [From Ohm's law]
I =
![(V)/(R)](https://img.qammunity.org/2022/formulas/physics/high-school/6k14p7s0rv82o95a3am9g5cdh1i5heztol.png)
I =
![(220)/(605)](https://img.qammunity.org/2022/formulas/mathematics/college/rdjk9u9tnyisjifeft46hp21f0u256wvnx.png)
I = 0.36A
iv. Get the power consumed by each lamp.
From Ohm's law, the power consumed is given by;
P = I²R
Where;
I = current flowing through the lamp
R = resistance of the lamp.
For the first lamp, power consumed is given by;
P = I²R [Where I = 0.36 and R = 121Ω]
P = (0.36)² x 121
P = 15.68W
For the second lamp, power consumed is given by;
P = I²R [Where I = 0.36 and R = 484Ω]
P = (0.36)² x 484
P = 62.73W
Therefore;
The power consumed in the lamp marked 100W - 110V is 15.68W
The power consumed in the lamp marked 100W - 220V is 62.73W