Answer:
The work done is 13680.8 J.
Step-by-step explanation:
The work done can be calculated as follows:
Where:
F: is the force
d: is the displacement = 40 m
The force acting on the boulder is given by:
![F = mgsin(\theta)](https://img.qammunity.org/2022/formulas/physics/college/alglj1286f6byvhq8uva84hir3osz48hsg.png)
Where:
m: is the mass = 100 kg
g: is the acceleration due to gravity = 10 m/s²
θ: is the angle = 20°
Then, the work is:
![W = mgsin(\theta)d = 100 kg*10 m/s^(2)*sin(20)*40 m = 13680.8 J](https://img.qammunity.org/2022/formulas/physics/college/v20rjyep979mfcyps2srzo5vs258fdr2bd.png)
Therefore, the work done is 13680.8 J.
I hope it helps you!