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A student pedaling a bicycle applies a net force of 250 N. The mass of the rider and the bicycle is 48 Kg. Assuming no friction is present, what is the acceleration of the bicycle and rider? (1 N= 1.0
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A student pedaling a bicycle applies a net force of 250 N. The mass of the rider and the bicycle is 48 Kg. Assuming no friction is present, what is the acceleration of the bicycle and rider? (1 N= 1.0 kg-m/sec?)

User Ashack
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1 Answer

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5.2 m/s. F=ma so 250=48a. Divide 250 by 48 and get your acceleration
User David Martins
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