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If (3x − 2)(3x + 2) = ax2 − b, what is the value of a?

User Pushpa
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2 Answers

6 votes


\sf{\bold{\blue{\underline{\underline{Given}}}}}

  • (3x − 2)(3x + 2) = ax2 − b⠀⠀⠀⠀


\sf{\bold{\red{\underline{\underline{To\:Find}}}}}

  • ⠀what is the value of a?⠀⠀⠀


\sf{\bold{\purple{\underline{\underline{Solution}}}}}

At first we have to solve the value of (3x-2)(3x+2)


  • \sf{(3x-2)(3x+2) }


  • \sf{3x(3x+2)-2(3x+2) }


  • \sf{9x^(2)+6x-6x-4 }


  • \sf{9x^(2)-4 }

According to the question,


  • \sf{ (3x − 2)(3x + 2) = ax^(2) − b }


  • \sf{9x^(2)-4=ax^(2)-b }


  • \sf{9x^(2)=ax^(2)~and~-4=-b }


  • \sf{a=9~and~b=4 }

⠀⠀⠀


\sf{\bold{\green{\underline{\underline{Answer}}}}}

Hence,

The value of a is 9

User Aabuhijleh
by
7.0k points
6 votes

(3x-2)(3x+ 2)

Multiply each term in one set of parentheses by the other terms:

3x x 3x =9x^2

3x x 2 = 6x

-2 x 3x = -6x

-2 x 2 = -4

Combine to get:

9x^2 + 6x - 6x -4

Combine like terms:

9x^2 - 4

The value of a would be 9.

User Fathurzero
by
7.4k points

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