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5 votes
If I=square root-1 then i^2=

User Kathrice
by
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1 Answer

4 votes

Answer:

i^−3 = i

i^−2 = −1

i^−1 = −i

i^0 = 1

i^1 = i

i^2 = −1

i^3 = −i

i^4 = 1

i^5 = i

i^ 6 = −1

See the pattern

User Evelina
by
4.2k points