Question

This question has multiple parts.

Part A:
A sample of unknown hydrate, AC-XH20, has a mass of 1.000 g before heating and a
mass of 0.781 g after heating. What is the experimental percentage of water in this
unknown hydrate?

Answer 1

21.9% is the experimental percentage of water in the unknown hydrate.

Step-by-step explanation:

The mass of an unknown hydrate = 1.000 g

The mass of hydrate after heating = 0.781 g

The mass of water lost due to heating = x

`1.000 g = 0.781 g + x\\x = 1.000 g - 0.781 g = 0.219 g`

The experimental percentage of water in the unknown hydrate:

`Water(\%)=\frac{\text{Mass of water lost after heating}}{\text{Mass of hydrate before heating}}* 100\\Water(\%)=(0.219 g)/(1.000 g)* 100\\=21.9\%`

21.9% is the experimental percentage of water in the unknown hydrate.