Question

Find the functional values of r(0), r(3) and r(-3) for the rational function.

Answer 1

Explanation:

Given function is,

`r(x)=(3x^3-7)/(x^2-6x+9)`

For x = 0, substitute the value of x in the given function.

`r(0)=(3(0)^3-7)/((0)^2-6(0)+9)`

`r(0)=(-7)/(9)`

For r = 3,

`r(3)=(3(3)^3-7)/((3)^2-6(3)+9)`

`r(3)=(81-7)/(9-18+9)`

`=(74)/((9-18+9))`

`=(74)/(0)`

Function is undefined at x = 3.

For x = -3,

`r(-3)=(3(-3)^3-7)/((-3)^2-6(-3)+9)`

`=(-81-7)/(9+18+9)`

`=(-88)/(36)`

`=-(22)/(9)`