134k views
2 votes
Find the perimeter of quadrilateral ABCD with vertices A(0, 4), B(4, 1), C(1, -3), and D(-3, 0).

User UnknownSPY
by
7.8k points

1 Answer

6 votes

Given:

The vertices of a quadrilateral ABCD are A(0, 4), B(4, 1), C(1, -3), and D(-3, 0).

To find:

The perimeter of quadrilateral ABCD.

Solution:

Distance formula:


d=√((x_2-x_1)^2+(y_2-y_1)^2)

Using the distance formula, we get


AB=√((4-0)^2+(1-4)^2)


AB=√((4)^2+(-3)^2)


AB=√(16+9)


AB=√(25)


AB=5

Similarly,


BC=√((1-4)^2+(-3-1)^2)


BC=5


CD=√((-3-1)^2+(0-(-3))^2)


CD=5

And,


AD=√((-3-0)^2+(0-4)^2)


AD=5

Now, the perimeter of the quadrilateral ABCD is:


P=AB+BC+CD+AD


P=5+5+5+5


P=20

Therefore, the perimeter of the quadrilateral ABCD is 20 units.

User Jean Claude Abela
by
8.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories