Question

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Answer 1

Given : A=(1,2)≡(x

1 ,y

1

​

) and B=(3,−2)≡(x

2

​

,y

2

​

)

Let M=(x,y) be the midpoint of AB

x=(

2

x

1

​

+x

2

​

​

) and y=(

2

y

1

​

+y

2

​

​

)

Then, x=

2

1+3

​

and y=

2

2−2

​

⟹x=2 and y=0

∴M=(2,0)

∴ Coordinates of the midpoint of AB is (2,0)

Explanation:

Answer 2

Bufjfjfmfmgmbbbjbjbubbubububububehiveg veto veto so 5+2=7