Question

Write a basic notation for


`a = ((b + d))/(2c)`

`z = (x)/(y + c)`

`c = (9c + 32)/(5)`





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Answer 1

`a = (b + c)/(2 * c)`

`z = x/(y + c)`

`c = (9 * c + 32)/5`

Step-by-step explanation:

Required

The expression in basic

To do this, we use () to group items, / as divide and * to combine factors

So, we have:

`(a)\ a = ((b + d))/(2c)`

In basic, it is:

`a = (b + c)/(2 * c)`

`(b)\ z = (x)/(y + c)`

In basic, it is:

`z = x/(y + c)`

`(c)\ c = (9c + 32)/(5)`

`c = (9 * c + 32)/5`