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I am trying to figure this question: 1 + tan^2A = Sec^2A
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3 votes
I am trying to figure this question:

1 + tan^2A = Sec^2A

User Mohit Kumar
by
7.9k points

1 Answer

5 votes

Answer:

see explanation

Explanation:

Using the Pythagorean identity

cos²A + sin²A = 1 ( divide terms by cos²A )


(cos^2A)/(cos^2A) +
(sin^2A)/(cos^2A) =
(1)/(cos^2A) , that is

1 + tan²A = sec²A ← as required

User Shalva Kakauridze
by
7.8k points
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